Do we assume the controller is a P controller with the value of kp??
Also, can you open the drop box so we can turn the quiz in early without having to wait until the day before its due?
It says so in Task 3. You *may* use $k_p$ if you wish in Task 2, but my initial intention was that you use $H(s)$. It does not make a difference.
Thank you! I just wanted to simplify the H(s) to a constant so I used kp.
When solving for w(t–>infinity), does the R ‘disappear’ if we assume kp is large, such that we are left with: r + 1/(kmkp)*d ???
No and yes. No, $R$ does not disappear, but it becomes very small compared to $k_p$. For large $k_p$ the factor in front of $r$ nears unity. Also, while $r + 1/(k_M k_p) d$ looks good, provided that you assume $R$ is small compared to $k_M k_p$, but you can make the point that with $k_p \to \infty$ the factor in front of $d$ goes to zero.
In either case, I have the impression that you are on the right track.
Can you define what Open Loop Versus Closed Loop is?
The closed-loop system is one where the output signal (i.e, the controlled variable) is in some fashion fed back into the controller and leads to a control action.
Conversely, the open-loop system is where the feedback loop is opened at some point, which means that no control action can take place. An open-loop configuration is useful to determine the behavior of the underlying system without active control.
See, for example, Section 5.3 in our book, especially Figure 5.3.
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